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lengths of the sides containing the rightthe circle,17. DrawandaABC having sides 8 cm,A circle is inscribed in10 cm and 12 cm as shown in figure,Find AD BE and CF1. |
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Answer» Here given,x+y = 8 cm ....(1) y+z = 12 cm .....(2)x+z = 10 cm .....(3) KUMAR Adding (1), (2) and (3), we get 2(x+y+z) = 30x+y+z = 30/2x+y+z = 15 .....(4)(4) - (2), we getx+12 = 15x = 15 - 12x =3(4) - (3), we get10+y = 15y = 15 - 10y = 5(4) - (1), we get 8+z = 15z = 15 - 8z = 7So,AD = 3 cmBE = 5 cmCF = 7 cm Answer. x+y=8, y+z=12, x+z=10, adding (x+y-8+y+z-12+x+z-10)=(2x+ 2y+ 2z=-30); 2(x+y+z)=30; x+y+z=30/2=15;; we get x+12=15; x=3; y=15-10=5; z=15-8=7 |
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