Lengths of the diagonals of a rhombus are 16 cm and 12 cm respectively

1.	Lengths of the diagonals of a rhombus are 16 cm and 12 cm respectively. Find the area of rhombus.
Answer» align="absmiddle" alt="\underline{ \underline{ \LARGE \pmb{\mathit{ {Given:}} }} }" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Cunderline%7B%20%5Cunderline%7B%20%20%5CLarge%20%5Cpmb%7B%5Cmathit%7B%20%7BGiven%3A%7D%7D%20%7D%7D%20%7D%20" title="\underline{ \underline{ \Large \pmb{\mathit{ {Given:}} }} }"> • Length of the diagonals of a rhombus are 16 cm and 12 cm. $\underline{ \underline{ \Large \pmb{\mathit{ {To \: calculate:}} }} }$ • Area of the rhombus. $\underline{ \underline{ \Large \pmb{\mathit{ {Calculation:}} }} }$ ✰ Here, we are given the the diagonals of a rhombus are 16 cm and 12 cm. We have to find the area of the rhombus. Basically we'll use the formula of the area of the rhombus in ORDER to find the area of the rhombus. ⠀⠀⠀⠀⠀_____________ As we know that, $\bigstar \: \boxed{\sf { {Area}_{(Rhombus)} = \dfrac{<klux>PRODUCT</klux> \: of \: diagonals}{2} }} \\$ $\longrightarrow \sf { {Area}_{(Rhombus)} = \dfrac{\cancel{16} \:cm \times 12 \: cm}{\cancel{2}} }$ $\longrightarrow \sf { {Area}_{(Rhombus)} = 8 \:cm \times 12 \: cm }$ $\longrightarrow \boxed{ \pmb{\rm \red{ {Area}_{(Rhombus)} = 96 \: {cm}^{2} }}}$ THEREFORE , area of the rhombus is 96 cm². _______________________________ $\underline{ \underline{ \Large \pmb{\mathit{ {More \: about \: Rhombus:}} }} }$ All the sides of a rhombus are equal. Perimeter = 4 × Side Rhombus is a parallelogram. Diagonals of the rhombus bisect each other. Diagonals bisect each other at 90°. Diagonals of the rhombus aren't equal. Opposite sides of the rhombus are equal. Opposite angles of the rhombus are equal. Area = (Product of diagonals/2)

Lengths of the diagonals of a rhombus are 16 cm and 12 cm respectively. Find the area of rhombus.

Answer»

align="absmiddle" alt="\underline{ \underline{ \LARGE \pmb{\mathit{ {Given:}} }} }" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Cunderline%7B%20%5Cunderline%7B%20%20%5CLarge%20%5Cpmb%7B%5Cmathit%7B%20%7BGiven%3A%7D%7D%20%7D%7D%20%7D%20" title="\underline{ \underline{ \Large \pmb{\mathit{ {Given:}} }} }">

• Length of the diagonals of a rhombus are 16 cm and 12 cm.

$\underline{ \underline{ \Large \pmb{\mathit{ {To \: calculate:}} }} }$

• Area of the rhombus.

$\underline{ \underline{ \Large \pmb{\mathit{ {Calculation:}} }} }$

✰ Here, we are given the the diagonals of a rhombus are 16 cm and 12 cm. We have to find the area of the rhombus. Basically we'll use the formula of the area of the rhombus in ORDER to find the area of the rhombus.

⠀⠀⠀⠀⠀_____________

As we know that,

$\bigstar \: \boxed{\sf { {Area}_{(Rhombus)} = \dfrac{<klux>PRODUCT</klux> \: of \: diagonals}{2} }} \\$

$\longrightarrow \sf { {Area}_{(Rhombus)} = \dfrac{\cancel{16} \:cm \times 12 \: cm}{\cancel{2}} }$

$\longrightarrow \sf { {Area}_{(Rhombus)} = 8 \:cm \times 12 \: cm }$

$\longrightarrow \boxed{ \pmb{\rm \red{ {Area}_{(Rhombus)} = 96 \: {cm}^{2} }}}$

THEREFORE , area of the rhombus is 96 cm².

_______________________________

$\underline{ \underline{ \Large \pmb{\mathit{ {More \: about \: Rhombus:}} }} }$

All the sides of a rhombus are equal.
Perimeter = 4 × Side
Rhombus is a parallelogram.
Diagonals of the rhombus bisect each other.
Diagonals bisect each other at 90°.
Diagonals of the rhombus aren't equal.
Opposite sides of the rhombus are equal.
Opposite angles of the rhombus are equal.
Area = (Product of diagonals/2)