Length of a rectangle is 2½ times its breadth. if it's perimeter is 7

1.	Length of a rectangle is 2½ times its breadth. if it's perimeter is 70m, find the length and breadth..??Plez answer ;-;
Answer» $\mathfrak{\large{\underline{\underline{Answer :-}}}}$ The Length is 25 m and Breadth is 10 m $\mathfrak{\large{\underline{\underline{Explanation :-}}}}$ Given : Length of the Rectangle = $\tt{2 \dfrac{1}{2}}$ of It's Breadth Perimeter of Rectangle = 70 m To FIND : The Length and Breadth Solution : Consider the Breadth as X Length will be $\tt{2 \dfrac{1}{2}x}$ ★ $\boxed{\sf{Perimeter=2(Length+Breadth)}}$ $\sf{\implies} \: 2\left[x + 2\dfrac{1}{2}x\right] = 70$ $\sf{\implies} \: 2\left[x + \dfrac{5}{2}x\right] = 70$ $\sf{\implies} \: 2x + 5x = 70$ $\sf{\implies} \:7x = 70$ $\sf{\implies} \:x = \dfrac{70}{7}$ $\sf{\implies} \:x = 10$ Breadth = 10 m $\rule{300}{1.5}$ ★ VALUE of $\tt{2 \dfrac{1}{2}x}$ $\sf{\implies} \: \dfrac{5}{\cancel{2}} \times \cancel{10}$ $\sf{\implies} \: 25$ Length = 25 m $\therefore$ The Length is 25 m and Breadth is 10 m $\rule{300}{1.5}$ $\mathfrak{\large{\underline{\underline{Verification :-}}}}$ $\sf{\implies} \: 2(25 + 10) = 70$ $\sf{\implies} \: 50 + 20 = 70$ $\sf{\implies} \: 70 = 70$ $\therefore$ The Length is 25 m and Breadth is 10 m