Lenght of a rectangle, if it's perimeter =32cm and width =5cm

1.	Lenght of a rectangle, if it's perimeter =32cm and width =5cm
Answer» ANSWER: $\huge{\fcolorbox{black}{red}{\blue{question}}}$ find the length of a rectangle, if it's perimeter is 32cm and WIDTH is 5cm. ${\fcolorbox{black}{pink}{\green{solution}}}$ $\underline\bold\red{length\:=\:<klux>11CM</klux>}$ ${\fcolorbox{black}{orange}{\purple{let's \:find \:out}}}$ $\underline\mathfrak\pink{using\:formula}$ $\underline\blue{perimeter \:of \:rectangle \:is\: <klux>2</klux>(l+b)}$ $\pink{given:-}$ $\green{perimeter\:=\:32cm}$ $\green{length\:=\: l}$ $\green{width\:=\:5cm}$ $\purple{so,}$ $= > 2(l + 5) = 32$ $= > 2l + 10 = 32$ $= > 2l = 32 - 10$ $= > 2l = 22$ $= > l = \frac{22}{2}$ $= > l = 11$ hence the length of the rectangle is 11cm. _______________________________________ perimeter of square = 4(sides) perimeter of rectangle = 2(l+b) perimeter of triangle** = a+b+c ________________________________________

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