\left(\frac{4 x-3}{2 x+1}\right)-10\left(\frac{2 x+1}{4 x-3}\right)=3,

1.	\left(\frac{4 x-3}{2 x+1}\right)-10\left(\frac{2 x+1}{4 x-3}\right)=3, x \neq \frac{-1}{2}, \frac{3}{4}
Answer» 16x2-24x+9-(40x2+20x+20x+10) / 8x2+4x-6x-3=3 (by cross multiplication) 16x2-24x+9-40x2-40x-10 / 8x2+4x-6x-3 = 3 -24x2-64x-1 / 8x2-2x-3 = 3 -24x2-64x-1=24x2-6x-9 48x2+58x-8=0 24x2+29x-4=0 Using factorisation, 24x2-3x+32x-4=0 (8x-1) =0 or (3x+4)=0 therefore, x= 1/8 or -4/3

\left(\frac{4 x-3}{2 x+1}\right)-10\left(\frac{2 x+1}{4 x-3}\right)=3, x \neq \frac{-1}{2}, \frac{3}{4}

Answer»

16x2-24x+9-(40x2+20x+20x+10) / 8x2+4x-6x-3=3 (by cross multiplication)

16x2-24x+9-40x2-40x-10 / 8x2+4x-6x-3 = 3

-24x2-64x-1 / 8x2-2x-3 = 3

-24x2-64x-1=24x2-6x-9

48x2+58x-8=0

24x2+29x-4=0

Using factorisation,

24x2-3x+32x-4=0

(8x-1) =0 or (3x+4)=0

therefore, x= 1/8 or -4/3