\left(\frac{4}{3} m-\frac{3}{4} n\right)^{2}+2 m n=\frac{16}{9} m^{2}+ – InterviewSolution

1.	\left(\frac{4}{3} m-\frac{3}{4} n\right)^{2}+2 m n=\frac{16}{9} m^{2}+\frac{9}{16} n^{2}
Answer» (4m/3 - 3n/4) ² + 2mn16m²/9 + 9n²/16 - 2mn + 2mn16m²/9 + 9n²/16

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