\left| \begin{array}{lll}{1} & {a} & {a^{2}} \\ {1} & {b} & {b^{2}} \\ – InterviewSolution

1.	\left\| \begin{array}{lll}{1} & {a} & {a^{2}} \\ {1} & {b} & {b^{2}} \\ {1} & {e} & {c^{2}}\end{array}\right\|=(a-b)(b-c)(c-a)
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