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\left. \begin{array} { l } { x ^ { 2 } - 3 x + 2 = 0 } \\ { x ^ { 2 } - x - 6 = 0 } \\ { x ^ { 2 } - 6 x + 8 = 0 } \\ { x ^ { 2 } - 5 x + 4 = 0 } \end{array} \right. |
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Answer» 1) x^2-3x+2=0 so (x-2)(x-1)=0so x=1,22) x^2-x-6=0so (x-3)(x+2)=0so x=-2,33) x^2-6x+8=0(x-4)(x-2)=0so x=2,44) x^2-5x+4=0(x-4)(x-1)=0x=1,4 |
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