\left. \begin{array} { l } { \text { If } \operatorname { sin } \theta + \operatorname { cos } \theta = 1 , \text { then } \operatorname { sin } \theta \operatorname { cos } \theta = } \\ { \text { (a) } 0 } & { \text { (b) } 1 } \\ { \text { (c) } 2 } & { \text { (d) } 1 / 2 } \end{array} \right.

\left. \begin{array} { l } { \text { If } \operatorname { sin } \theta

1.	\left. \begin{array} { l } { \text { If } \operatorname { sin } \theta + \operatorname { cos } \theta = 1 , \text { then } \operatorname { sin } \theta \operatorname { cos } \theta = } \\ { \text { (a) } 0 } & { \text { (b) } 1 } \\ { \text { (c) } 2 } & { \text { (d) } 1 / 2 } \end{array} \right.
Answer» sin + cos = 1sqauring both sidessin² + cos² + 2sinsin = 1so sincos = 0/2 = 0option (c) is correct