\left. \begin{array} { l } { \text { If } f ( x ) = \operatorname { log } _ { e } ( \frac { 1 + x } { 1 - x } ) , g ( x ) = \frac { 3 x + x ^ { 3 } } { 1 + 3 x ^ { 2 } } \text { and } } \\ { \text { gof } ( t ) = g ( f ( t ) ) , \text { then what is gof } ( \frac { e - 1 } { e + 1 } ) } \\ { ( a ) 2 } & { ( b ) 1 } & { ( c ) 0 } & { ( d ) } \end{array} \right.

\left. \begin{array} { l } { \text { If } f ( x ) = \operatorname { lo

1.	\left. \begin{array} { l } { \text { If } f ( x ) = \operatorname { log } _ { e } ( \frac { 1 + x } { 1 - x } ) , g ( x ) = \frac { 3 x + x ^ { 3 } } { 1 + 3 x ^ { 2 } } \text { and } } \\ { \text { gof } ( t ) = g ( f ( t ) ) , \text { then what is gof } ( \frac { e - 1 } { e + 1 } ) } \\ { ( a ) 2 } & { ( b ) 1 } & { ( c ) 0 } & { ( d ) } \end{array} \right.
Answer»