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\left. \begin array l l ( x %2B 2 ) ^ 3 = x ( x ^ 2 - 1 ) & ( B ) \\ ( x - 2 ) ( x %2B 2 ) = 5 & \text (D) x ^ 2 %2B \frac 1 x ^ 2 = 2 \end array \right. |
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Answer» Option Dx²+1/x² = 2As, x² comes in denominator. |
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