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\left| \begin{array} { l l l } { a } & { b } & { c } \\ { b } & { c } & { a } \\ { c } & { a } & { b } \end{array} \right| = 3 a b c - a ^ { 3 } - b ^ { 3 } - c ^ { 3 } |
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Answer» L.H.S.=a(bc-a^2)-b(b^2-ac)+c(ab-c^2) =abc-a^3-b^3+abc+abc-c^3 =3abc-a^3-b^3-c^3 =R.H.S.Hence Proved |
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