\left. \begin{array} { l l } { 2 x ^ { 2 } + \frac { x - 1 } { 5 } = 0

1.	\left. \begin{array} { l l } { 2 x ^ { 2 } + \frac { x - 1 } { 5 } = 0 } & { ( \text { ii } ) 9 x + 1 = 4 x ^ { 2 } } \\ { 2 x ^ { 2 } + 5 x - 2 } & { = 0 } \end{array} \right.
Answer» i) 2x²+(x-1)/5 = 0 => 10x²+x-1 = 0 x = (1/4)(-1±√(1+4.10.1))x = -1/4+√41/4 , -1/4-√41/4 ii) 4x²-9x-1 = 0 here D = 9²-4.4.(-1) = 9²+16 = 97 so, x =( -(-9)±√97)/42 = (9±√97)/8 = 9/8+√97/8 , 9/8-√97/8 iii) 2x²+5x-2 = 0 D = 5²-4.2.(-2) = 25+16 = 41 so x =( -5±√41)/2.2 = -5/4+√41/4 , -5/4-√41/4

\left. \begin{array} { l l } { 2 x ^ { 2 } + \frac { x - 1 } { 5 } = 0 } & { ( \text { ii } ) 9 x + 1 = 4 x ^ { 2 } } \\ { 2 x ^ { 2 } + 5 x - 2 } & { = 0 } \end{array} \right.

Answer»

i) 2x²+(x-1)/5 = 0 => 10x²+x-1 = 0 x = (1/4)*(-1±√(1+4.10.1))x = -1/4+√41/4 , -1/4-√41/4

ii) 4x²-9x-1 = 0 here D = 9²-4.4.(-1) = 9²+16 = 97

so, x =( -(-9)±√97)/4*2 = (9±√97)/8 = 9/8+√97/8 , 9/8-√97/8

iii) 2x²+5x-2 = 0 D = 5²-4.2.(-2) = 25+16 = 41 so x =( -5±√41)/2.2 = -5/4+√41/4 , -5/4-√41/4