\left. \begin{array} { l l } { 2 } & { f ( x ) = \sqrt { x - 1 } + \sq

1.	\left. \begin{array} { l l } { 2 } & { f ( x ) = \sqrt { x - 1 } + \sqrt { 6 - x } } \\ { 4 } & { f ( x ) = \frac { 1 } { \sqrt { x - [ x ] } } } \end{array} \right.
Answer» f(x) = √x-1 +√6-x the domain of this function should be such that . the root value should not be less than <0so the fomain is [1,6] f(x) = 1/√(x-[x]) = 1/√{x} we know that {x} is fractional part of x , and it is Zero at every integer.. so, the domain should not be any integer... so, domain = R - I.

\left. \begin{array} { l l } { 2 } & { f ( x ) = \sqrt { x - 1 } + \sqrt { 6 - x } } \\ { 4 } & { f ( x ) = \frac { 1 } { \sqrt { x - [ x ] } } } \end{array} \right.

Answer»

f(x) = √x-1 +√6-x

the domain of this function should be such that . the root value should not be less than <0so the fomain is [1,6]

f(x) = 1/√(x-[x]) = 1/√{x}

we know that {x} is fractional part of x , and it is Zero at every integer.. so, the domain should not be any integer...

so, domain = R - I.