\left. \begin{array} { l } { \frac { 1 + \operatorname { sin } 2 \theta + \operatorname { cos } 2 \theta } { 1 + \operatorname { tan } 2 \theta + \operatorname { cos } 2 \theta } = } \\ { 1 + \operatorname { tan } \theta - \operatorname { cos } 2 \theta } \\ { ( 1 ) \frac { 1 } { 2 } \operatorname { tan } \theta ( 2 ) \frac { 1 } { 2 } \operatorname { cot } \theta ( 3 ) \operatorname { tan } \theta ( 4 ) \operatorname { cot } \theta } \end{array} \right.

\left. \begin{array} { l } { \frac { 1 + \operatorname { sin } 2 \thet

1.	\left. \begin{array} { l } { \frac { 1 + \operatorname { sin } 2 \theta + \operatorname { cos } 2 \theta } { 1 + \operatorname { tan } 2 \theta + \operatorname { cos } 2 \theta } = } \\ { 1 + \operatorname { tan } \theta - \operatorname { cos } 2 \theta } \\ { ( 1 ) \frac { 1 } { 2 } \operatorname { tan } \theta ( 2 ) \frac { 1 } { 2 } \operatorname { cot } \theta ( 3 ) \operatorname { tan } \theta ( 4 ) \operatorname { cot } \theta } \end{array} \right.
Answer»