1.

\left. \begin{array} { l } { 30 \div ( 3 + 2 ) - 3 \text { of } 3 + 2 \times ( 6 + 3 ) } \\ { 200 \div 2 ( 2 \text { of } 5 ) - ( 10 \times 10 - 5 ) } \end{array} \right.

Answer»

a) 30÷(3+2) -3of3 +2×(6+3)= 30/5 -9 +2*(9)= 6-9+18 = 15

b) 200÷2*(2of5) -(10×10-5)= 200÷(2*10) -(100-5)= 10-(100-5)= 10+5-100= 15-100= -85

Your Ans:a is correct but And:b is wrong



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