\left. \begin{array} { l } { 3 ^ { \circ } = p , \text { write } \oper

1.	\left. \begin{array} { l } { 3 ^ { \circ } = p , \text { write } \operatorname { cos } 43 ^ { \circ } \text { in terms } } \\ { 0 ^ { \circ } = a , \text { write } \operatorname { sin } 50 ^ { \circ } \text { in terms } } \\ { \text { e value of } \operatorname { cos } ^ { 2 } 72 ^ { \circ } + \operatorname { sin } ^ { 2 } 72 ^ { \circ } } \end{array} \right.
Answer» a)sin43= pcos43= √1-p^2b)cot50=a=costheta/sinthetasin50= 1/√1+a^2 c) 1

\left. \begin{array} { l } { 3 ^ { \circ } = p , \text { write } \operatorname { cos } 43 ^ { \circ } \text { in terms } } \\ { 0 ^ { \circ } = a , \text { write } \operatorname { sin } 50 ^ { \circ } \text { in terms } } \\ { \text { e value of } \operatorname { cos } ^ { 2 } 72 ^ { \circ } + \operatorname { sin } ^ { 2 } 72 ^ { \circ } } \end{array} \right.

Answer»

a)sin43= pcos43= √1-p^2b)cot50=a=costheta/sinthetasin50= 1/√1+a^2

c) 1