1.

LE 1 AD, BE and CF, the altitudes of Δ ABC are equal, prove that Δ ABC is anaquilateral triangle.

Answer»

In triangle ABE and triangle ACF

BE=CF (Given)

∠A=∠A (Common)

∠AEB=∠AFC=90°

By AAS congruent rule ABE ≅ ACF

AB=AC (CPCT)

Similarly

BCF ≅ ABD

AB=BC

AC=BC

AB=AC

AB = BC = AC..... Proved

The triangle is a equaliteral triangle .



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