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lasIf a, ß are the reuves of the 2n-Sat 7, then findthe polynomials whose zeewes are 25+ 38, 32+28. |
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Answer» 2x^2-5x+7 let p,q be zerosp+q= 5/2pq= 7/2sum of given zeros 2p+3q+3p+2q= 5p+5q= 5(p+q)= 5(-5/2)= -25/2product of zeros(2p+3q)(3p+2q)6p^2+4pq+9pq+6q^26(p^2+q^2)+13pq6{(p+q)^2-2pq} +13pq6{25/4-2×7/2)+13(7/2)6{25-28/4}+91/23(-3)/2+91/2-9+91/2= 82/2=41polynomial =x^2-x(sum of zeros)+product of zerosx^2-x(-25/2)+412x^2+25x+82 2x+25x+82is correct answer |
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