L2, lha the AP.of an AP is equal to 6 times its 2nd term. If its 5th t

1.	L2, lha the AP.of an AP is equal to 6 times its 2nd term. If its 5th term is 22, find the AP25the 9th term(2,7,12,.
Answer» Let the first term be "a" and common difference "d" Ninth term = a + (9 - 1)d = a + 8dSecond term = a + (2 - 1)d = a + d A/Q,a + 8d = 6(a + d)a + 8d = 6a + 6d- 5a + 2d = 0 Fifth term = a + (5 - 1)d = a + 4d = 22 - 5a + 2d = 0a + 4d = 22 Solving the equations ,- 11a = - 22a = 2 Now, 2 + 4d = 224d = 20d = 5 First term = 2Second term = a + d = 2 + 5 = 7Third term = a + 2d = 2 + 10 = 12Fourth term = a + 3d = 2 + 15 = 17Fifth term = a + 4d = 2 + 20 = 22 The required AP = 2 , 7 , 12 , 17 , 22 Like my answer if you find it useful!

L2, lha the AP.of an AP is equal to 6 times its 2nd term. If its 5th term is 22, find the AP25the 9th term(2,7,12,.

Answer»

Let the first term be "a" and common difference "d"

Ninth term = a + (9 - 1)d = a + 8dSecond term = a + (2 - 1)d = a + d

A/Q,a + 8d = 6(a + d)a + 8d = 6a + 6d- 5a + 2d = 0

Fifth term = a + (5 - 1)d = a + 4d = 22

- 5a + 2d = 0a + 4d = 22

Solving the equations ,- 11a = - 22a = 2

Now, 2 + 4d = 224d = 20d = 5

First term = 2Second term = a + d = 2 + 5 = 7Third term = a + 2d = 2 + 10 = 12Fourth term = a + 3d = 2 + 15 = 17Fifth term = a + 4d = 2 + 20 = 22

The required AP = 2 , 7 , 12 , 17 , 22

Like my answer if you find it useful!