L IF PE and FB are tangents to the circle with centre O such that ZAPB

1.	L IF PE and FB are tangents to the circle with centre O such that ZAPB- 50, find the 204BA.P-15090
Answer» Since OA is perpendicular to PA and also, OB is perpendicular to PB ∠APB + ∠AOB = 180° 50°+ ∠AOB = 180° ∠AOB = 180° – 50° = 130° In △AOB, OA = OB = radii of same circle ∠OAB = ∠OBA = x ( say ) Again, ∠OAB + ∠OBA + ∠AOB = 180° x +x + 130° = 180° 2x = 180° – 130° = 50° X = 25° Hence, ∠OAB =25°

L IF PE and FB are tangents to the circle with centre O such that ZAPB- 50, find the 204BA.P-15090

Answer»

Since OA is perpendicular to PA and also, OB is perpendicular to PB

∠APB + ∠AOB = 180°

50°+ ∠AOB = 180°

∠AOB = 180° – 50° = 130°

In △AOB,

OA = OB = radii of same circle

∠OAB = ∠OBA = x ( say )

Again, ∠OAB + ∠OBA + ∠AOB = 180°

x +x + 130° = 180°

2x = 180° – 130° = 50°

X = 25°

Hence, ∠OAB =25°