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L.C.M. and H.C.Fe. What will be the total number of integers between 100 and 200can be divided by both 9 and 6?(al 5bl 6(c) 7s(d) 8 |
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Answer» Any number that is divisible by 9 and 6 is also divisible by their LCM, i.e., 18.Now, on dividing 100 by 18, the remainder = 10. Thus, the smallest number greater than 100 that is divisible by 18 =100+(18−10)=108.100+(18−10)=108.Similarly, remainder on dividing 200 by 18 = 2, and the largest number smaller than 200 that is divisible by 18 = 198.Number of numerals between 108 and 198 (both inclusive) that are divisible by 18 =(198−108)/18+1=6.(198−108)/18+1=6.Therefore,there are 6 numbers between 100 and 200 that are divisible by both 6 and 9. |
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