Saved Bookmarks
| 1. |
L and M are mid points of two equal chords AB and CD of a circle with center O.Prove that `/_OLM=/_OML` and `/_ALM=/_CML` |
|
Answer» `PQ=SR` `(PQ)/2 = (SR)/2` `XQ = YR` now `/_ `OCM is an isoceles `/_ ~ /_ O` now`/_ ALM = /_ALO - /_OLM` `= 90 - /_OLM` `/_CML = /_CMO- /_OML = 90 - /_OML` by comparing the 2 equations so `/_OLM = /_OML` so, `/_ALM = /_CML` |
|