Kunal’s age is seven times the age of his son. Ten years later, his

1.	Kunal’s age is seven times the age of his son. Ten years later, his age will be thrice the age of his son then. Taking Kunal's age to be x years and the son's age to be y years, find their present ages.
Answer» Given : Kunal's AGE is 7 TIMES the age of his son. 10 years later , his age will be thrice the age of his son then. To find : Their present ages. Solution : Consider, Present age of Kunal = x years Present age of his son = y years ${\underline{\sf{According\:to\: the\:1st\: condition:-}}}$ Kunal's age is 7 times the age of his son. $\to\sf{x=7y...................(1)}$ ${\underline{\sf{According\:to\: the\:2nd\: condition:-}}}$ 10 years later , his age will be thrice the age of his son then. 10 years later, Age of Kunal = (x+10) years Age of his son = (y+10) years $\to\sf{x+10=3(y+10)}$ $\to\sf{x+10=3y+30}$ Put x = 7y from eq(1). $\to\sf{7y+10=3y+30}$ $\to\sf{7y-3y=30-10}$ $\to\sf{4y=20}$ $\to\sf{y=5}$ Present age of son = 5 years Present age of Kunal = 7×5 = 35 years.