1.

KoogleTest Level-3 (Unit-6)A force of 0.01 N is exerted on a charge of 1.2 x 10-5 C. at a certain point. The electric field at that point isA) 5.3 x 106 N/CB) 8.3 x 106 N/CC) 5.3 x 106 N/CD) 8.3 x 102 N/C

Answer»

Here applying

Formula:

e = \frac{<klux>F</klux>}{q}

where e is electric FIELD and f is force.

f here is = 0.01N

q =

1.2 \times {10}^{ - 5}

so,

\frac{0.01}{1.2 \times {10}^{ - 5} } \\ solving \: this \: we \: get \\ e = 8.3 \times {10}^{2} n {c}^{ - 1}

Hope this gonna help you ♡(∩o∩)♡


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