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Kinetic energy of a particle (K.E) moving along x-axis depends on its position (x) and time (t) as KE = At^2/B+x^1/2 +Cx^3/2 / D+t^2 . The dimensional formula of ABC/D is |
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Answer» placement of a particle at time t is given s = ut + 1/2at2At time (t - 1), the displacement of a particle is given byS' = u (t-1) + 1/2a(t-1)2 So, Displacement in the LAST 1 second is,St = S - S'= ut + 1/2 at2 – [u(t-1)+1/2 a(t-1)2 ]= ut + 1/2at2 - ut + u - 1/2a(t - 1)2= 1/2at2 + u - 1/2 a (t+1-2t) = 1/2at2 + u - 1/2at2 - a/2 + ATS = u + a/2(2t - 1)(B) Putting the values of u = 2 m/s, a = 1 m/s2 and t = 5 sec, we getS = 2 + 1/2(2 x 5 - 1) = 2 + 1/2 x 9= 2 + 4.5 = 6.5 m (Ans): 6.5 m |
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