х3эх||==, show that +2a be3xyzabcQJ x 3 )63 х. – InterviewSolution

1.	х3эх\|\|==, show that +2a be3xyzabcQJ x 3 )63 х.
Answer» x/a=y/b=z/c=k(let)x=ak, y= bk, z=ckLHSx^3/a^3+y^3/b^3+z^3/c^3=a^3k^3/a^3+b^3k^3/b^3+c^3k^3/c^=3k^3RHS= 3xyz/abc=3ak.bk.ck/abc=3k^3LHS=RHSproved

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