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kettle rated at 2.8 KW contains a mass of 465 G of water at a temperature of 24 degree celsius the cattle is switched on for a time of 2.5 minutes. during that time 92% of the input energy is transferred to the water calculate the mass of water that is evaporated​

Answer» LAW of conservation of energy. energy given by HEATER must be equal to the SUM of energy gained by water and energy LOST from the lid.Pt=ms Δθ + energy lost1000t=2×4.2×10 3 ×50+160t840t=8.4×10 3 ×50=500sec=8min 20secmake me brainlist


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