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Keeping the volume constant, the pressure of the gas is increased by 10% of its original value by increasing the temperature from 27^(0) C. Find the final temperature. |
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Answer» Solution :Initial PRESSURE of the gas `(P_(1)) = P ` Final pressure of the gas `(P_(2)) = (110)/(100)` P Initial temperature `t_(1)^(0) C = 27^(0)` C `T_(1) = 27 + 273 = 300` K Final temperature `t_(2)^(0) C `= ? At constant volume, according to Charles law `(P_(1))/(T_(1)) = (P_(2))/(T_(2))` `T_(2) = (P_(2))/(P_(1)) T_(1) = (110P//100)/(P) XX 300 = 330` `t_(2) = 330 - 273 = 57^(0)` C |
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