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-Kar¡Find length of altitude of an equilateral triangle having area 9/3 cm2 . |
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Answer» Let each side of equilateral triangle = aArea = 9√3 cm sq.Area of equilateral triangle = √3 / 4 × side sq.9√3 = √3 /4 × a9 × 4 = √3 / √3 × a36 = 1 × aa = 36 Now, Area = 1/2*base*altitude9√3 = 1/2* 36 *altitude Altitude = 18√3/36 = √3/2 Therefore, altitude of triangle = √3/2 cm thanks suksma |
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