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Ka for `H_(3)BO_(3) "is" 5.8xx10^(-10)` what buffer component ratio `[NaH_(2)BO_(3)(aq.)]//[H_(3)BO_(3)(aq.)]` would be needed to make a buffer solution of pH=10.A. 10B. 0.18C. 4.3D. 5.8 |
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Answer» Correct Answer - D `pH=pKa+log.([NaH_(2)BO_(3)])/([H_(3)BO_(3)])` `[H^(+)]=Kaxx([H_(3)BO_(3)])/([NaH_(2)BO_(3)])` `10^(-10)=5.8xx10^(-10)xx([H_(3)BO_(3)])/([NaH_(2)BO_(3)])` |
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