Saved Bookmarks
| 1. |
K² + 4k =5 find KX=k² and y=k |
|
Answer» =k2+4k-5=0 =K2+5k-k-5 =k(k+5) -1(k+5) so, (k-1) (k+5) =0 Either,=(k-1) =0=k=1 it is possibleand,= k+5=0= k=-5 it is not possiblehence,the VALUE of k=1 |
|