1.

K² + 4k =5 find KX=k² and y=k

Answer»

ANSWER:

=k2+4k-5=0

=K2+5k-k-5

=k(k+5) -1(k+5)

so, (k-1) (k+5) =0

Either,

=(k-1) =0

=k=1 it is possible

and,

= k+5=0

= k=-5 it is not possible

hence,

the VALUE of k=1



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