k*x %2B 3*y=k - 3 – InterviewSolution

1.	kx %2B 3y=k - 3
Answer» The given system of equations: kx + 3y = 3 kx + 3y - 3 = 0 ….(i) 12x + ky = 6 12x + ky - 6 = 0 ….(ii) These equations are of the following form: a1x+b1y+c1 = 0, a2x+b2y+c2 = 0 where, a1 = k, b1= 3, c1 = -3 and a2 = 12, b2 = k, c2 = –6 In order that the given system has no solution, we must have:

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