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K_(sp) of AI(OH)_3 is 1xx10^(-15) M. At what pH does 1.0xx10^(-3) M AI^(3+)precipitate on the addition of buffer of NH_4 CI and NH_4 OH solution. |
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Answer» Solution :`AI(OH)_3 hArr AI+_((aq))^(3+)+3OH_((aq))^(-)` `[K_(sp)=pAI^(3+)][OH^-]^3` `AI(OH)_3` precipitates when `[AI^(3+)][OH^(-)]^3 GT K_(sp)` `[1xx10^(-3)][OH^(-)]^3 gt 1xx10^(-15)` `[OH]^3 gt 1xx10^(-12)` `[OH^-] gt 1xx10^(-4) M` `[OH^-]=1xx10^(-4) M` `POH=-log_(10)[OH^-]` `=-LOG[1xx10^(-4)]=4` `PH=14-4=10` Thus, `AI(OH)_3` precipitates at a `pH of 10.` |
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