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`K_2 CrO_4` oxidises `KI` in the presence of `HCl` to `I_2`. The equivalent weight of the `K_2 CrO_4` is.A. `(M_w)/(2)`B. `M_w xx (2)/(3)`C. `(M_w)/(3)`D. `(M_w)/(6)` |
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Answer» Correct Answer - C `3e^- + underset(x=6)(CrO_4^(2-)) rarr underset((x=6-3=3))underset(x=3)([Cr(OH)_4]^(Theta))` `:. E_w = (M_w)/(3)`. |
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