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(k-1)x^2=kx-1 find K so that one root is -3 |
| Answer» (k-1)x^2=kx-1This can be written as;(k-1)x^2-(kx-1)=0(k-1)x^2-kx+1=0Put x= -3 as this is a zero of polynomial: (k-1)(-3)^2-k(-3)+1=0 (k-1)(9)+3k+1=0 9k-9+3k+1=0 9k+3k-9+1=0 12k-8=0 12k=8 k=8/12 k=2/3So, the value of k is 2/3 so that one of the zero of this polynomial is -3.#Hope this may be helpful for you... | |