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君1In figure, ΔFEC ΔGDB and L122. prove that ΔADE ~AABC.OTO |
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Answer» Given :∆FEC≅∆GBD , SO From CPCT WE GET, BD=CE----------------- ( 1 ) ALSO GIVEN :∠1 =∠2 , SO FROM BASE ANGLE THEOREM IN∆ADE WE GET AD =AE------------------------ ( 2 ) From equation 1 and 2 we get ADBD=AECE, So from converse of B.P.T. we get DE | | BC THEN , ∠1 =∠3 ( CORRESPONDING ANGLES AS DE | | BC AND AB IS TRANSVERSAL LINE ) AND ∠2 =∠4 ( CORRESPONDING ANGLES AS DE | | BC AND AC IS TRANSVERSAL LINE ) FROM ABOVE TWO EQUATIONS WE CAN SAY THAT : ∆ADE~∆ABC( ByAArule )( Hence proved) |
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