1.

Judge the equivalent resistance when the following are connected in parallel: a) 1 Omega and 10^6 Omega (b) 1 Omega and 10^3 Omega and 10^6 Omega

Answer»

SOLUTION :When two or more resistances `R_1,R_2,R_3` etc are joined in PARALLEL, the resultant RESISTANCE in parallel arrangement `R_p` is given by
`1/R_p=1/R_1+1/R_2+1/R_3+…`
(a) When `R_1=1 Omega and R_2=10^6 Omega`
`1/R_p=1/1+1/10^6=1+10^-6=1 IMPLIES R_p=1 Omega`
(b) When `R_1=1 Omega, R_2=10^3 Omega and R_3=10^6 Omega`
`1/R_p=1/1+1/10^3+1/10^6=1+10^-3+10^-6=1thereforeR_p=1 Omega`


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