Jo. Find the equation of the perpendicular from the origin to the line

1.	Jo. Find the equation of the perpendicular from the origin to the line x + 4y + 4z – 27=0,2x + 2y + 5z - 21=0. Also, find the co-ordinates of the foot of the perpendicular,1 Put the equation r = qy + b, z = cy + d in the symmetric form.
Answer» ANSWER: dhfhdjndjgktkdkskrkdnnw ESSA

Jo. Find the equation of the perpendicular from the origin to the line x + 4y + 4z – 27=0,2x + 2y + 5z - 21=0. Also, find the co-ordinates of the foot of the perpendicular,1 Put the equation r = qy + b, z = cy + d in the symmetric form.

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ANSWER:

dhfhdjndjgktkdkskrkdnnw ESSA

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Jo. Find the equation of the perpendicular from the origin to the line x + 4y + 4z – 27=0,2x + 2y + 5z - 21=0. Also, find the co-ordinates of the foot of the perpendicular,1 Put the equation r = qy + b, z = cy + d in the symmetric form.​

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Jo. Find the equation of the perpendicular from the origin to the line x + 4y + 4z – 27=0,2x + 2y + 5z - 21=0. Also, find the co-ordinates of the foot of the perpendicular,1 Put the equation r = qy + b, z = cy + d in the symmetric form.