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Jane is 6 years older than her younger sister. After 10 years, the sum of their ages will be 50 years. Find their present ages. |
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Answer» LET his sister's age is X Then Jane's age = X+6 After 10 yrs sum of their age = 50yrs X+(X+6)+10 = 50 2X +16 = 50 2X = 34 X = 17 X+6 = 23 Hence Jane's age = 23 & her YOUNGER sister's age = 17 |
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