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Ive the following: (3 marks each)Which term of the arithemetic prograssion 3, 10, 17... would be 84 more than its 13th(12)term ? |
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Answer» a = 3 d = 7 , 13th term will be , a₁₃ = a + 12d a₁₃ = 3 + 12×7 a₁₃= 3+ 84 = 87 Since , 84 more than its 13th term ,so , value of term will be = 87 + 84 = 171 So value of term is 171 Now using , aₙ = a+(n-1)d 171 = 3 + 7n - 7 171 + 4 = 7n 175/7 = n n = 25 , So 25th term will be 84 more than its 13th term , Verification :- a₂₅ = a + 24 d a₂₅ = 3 + 24×7 a₂₅ = 3 + 168 = 171 |
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