1.

Ive the following: (3 marks each)Which term of the arithemetic prograssion 3, 10, 17... would be 84 more than its 13th(12)term ?

Answer»

a = 3

d = 7 ,

13th term will be ,

a₁₃ = a + 12d

a₁₃ = 3 + 12×7

a₁₃= 3+ 84 = 87

Since , 84 more than its 13th term ,so ,

value of term will be = 87 + 84 = 171

So value of term is 171

Now using ,

aₙ = a+(n-1)d

171 = 3 + 7n - 7

171 + 4 = 7n

175/7 = n

n = 25 ,

So 25th term will be 84 more than its 13th term ,

Verification :-

a₂₅ = a + 24 d

a₂₅ = 3 + 24×7

a₂₅ = 3 + 168 = 171



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