1.

Iv) f(x) = 3x² + x² - 20x +12.3x3 + x² - 20x +12. g(x)= 3x-2​

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Answer:

ANSWER

Given f(x)=3x

3

+x

2

−20x+12 the G(x)=3x−2 is the FACTOR

If g(x)=3x−2 is factor then g(x)=3x−2=0 or x=

3

2

Replace x by

3

2

in f(x) we get

f(x)=3x

3

+x

2

−20x+12

f(

3

2

)=3(

3

2

)

3

+(

3

2

)

2

−20(

3

2

)+12

⇒f(

3

2

)=3×

27

8

+

9

4

−20×

3

2

+12

f(

3

2

)=

9

8

+

9

4

3

40

+12

f(

3

2

)=

9

8+4−120+108

=

9

120−120

=0

So f(x)is ZERO by g(x) then g(x) =3x-2 is factor of f(x)=3x

3

+x

2

−20x+12



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