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(iv)1 + secAsec A.sin' A1 -cos A[Hint : Simplify LHS and RHS separatelyA1moet |
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Answer» LHS1+secA/secA1+1/cosA /1/cosA= solve rhs sin^2A 1+secA/secA= sin^2A/1-cosALHS1+secA/secA= 1+1/cosA/1/cosA=cosA+1/cosA / 1/cosA= cosA+1RHSsin^2A/1-cosA1-cos^2A/1-cosA= (1+cosA)(1-cosA)/(1-cosA)= 1+ cosALHS=RHSproved |
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