1.

It was observed that a charge of 2×10^-8 coulombs experienced a force of 50Newton a uniform electric field find the value of the electric field intensity

Answer» ONG>Answer:

2.5×10^9

as we KNOW: E=F/q

E= 50/2×10^-8

E= 2.5×10^9



Discussion

No Comment Found

Related InterviewSolutions