1.

it takes six days for two men and three women working together to complete a work. three men would do the same work five days sooner than nine women. how many times does the output of a man exceed that of a woman?

Answer»

Given:

It takes six days for two men and three women working together to complete a work. three men would do the same work five days sooner than nine women.  

To FIND:

How many TIMES does the output of a man exceed that of a woman?

SOLUTION:

From given, let us consider the FOLLOWINGS:

If 9 women, 1-day work = 1/x ---(1)

So 3 men, 1 day work = 1/(x-5) ---(2)

Also given 3 women and 2 men 1-day work = 1/6 ---(3)

From (1), we have,

3 women 1-day work = 1/3x

From (2), we have,

2 men 1 day work = 2/[3(x-5)]

Equation (3) can be represented as, 1/3x + 2/[3(x-5)]= 1/6

Solving the equation, we GET, x = 10

So 1 woman 1 day work=1/(9 × 10)= 1/90 and

1 man 1 day work=1/3(10-5)= 1/15

The output of men exceeds that of a women = (1/15)/(1/90)= 6 times

Therefore, 6 times the output of a man exceeds that of a woman



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