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it takes six days for two men and three women working together to complete a work. three men would do the same work five days sooner than nine women. how many times does the output of a man exceed that of a woman? |
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Answer» Given: It takes six days for two men and three women working together to complete a work. three men would do the same work five days sooner than nine women. To FIND: How many TIMES does the output of a man exceed that of a woman? From given, let us consider the FOLLOWINGS: If 9 women, 1-day work = 1/x ---(1) So 3 men, 1 day work = 1/(x-5) ---(2) Also given 3 women and 2 men 1-day work = 1/6 ---(3) From (1), we have, 3 women 1-day work = 1/3x From (2), we have, 2 men 1 day work = 2/[3(x-5)] Equation (3) can be represented as, 1/3x + 2/[3(x-5)]= 1/6 Solving the equation, we GET, x = 10 So 1 woman 1 day work=1/(9 × 10)= 1/90 and 1 man 1 day work=1/3(10-5)= 1/15 The output of men exceeds that of a women = (1/15)/(1/90)= 6 times Therefore, 6 times the output of a man exceeds that of a woman |
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