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It is required to fix a pipe such that water flowing through it at a speed of 7 metres per minute fills a tank of capacity 440 cubic metres in 10 minutes. The inner radius of the pipe should be: (a) √2 m (b) 2 m (c) \(\frac12\) m (d) \(\frac1{\sqrt2}\) m |
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Answer» (a) \(\sqrt2\) m Let the inner radius of pipe be r m. Then, 440 = \(\frac{22}{7}\times{r}^2\times7\times10\) ⇒ r2 = \(\frac{440}{22\times10} = 2\) ⇒ r = \(\sqrt2\) m. |
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