1.

It is given that s=5+7√3/2-11√3= -(a+69√3/b) a and b are integers the value of b- a

Answer»

S=5+7√3/2-11√3=(5+7√3)(2+11√3)/(2-11√3)(2+11√3)=
10+55√3+14√3+231/4-99= -(241+69√3)/95. please corect the QUESTION is a in numerator or DENOMINATOR??if a is in numerator then b-a=-172. Or if a is in denominator then b-a=-26.



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