It being given that √2=1.414,√3=1.732,√5=2.236 and √10=3.162,

1.	It being given that √2=1.414,√3=1.732,√5=2.236 and √10=3.162, find the value to three places of decimals of each of the following1) 2/√52) 2-√3/√33) √10-√5/√2help box(answer), 1) 0.894 2) 0.1553),0.655 please tell me explanation
Answer» ANSWER: The GIVEN EXPRESSIONS are EVALUATED after RATIONALIZING its denominators. Given: $\sqrt2=1.414,\sqrt3=1.732,\sqrt5=2.236\:and\:\sqrt{10}=3.162$ 1. $\frac{2}{\sqrt5}$ $=\frac{2}{\sqrt5}\frac{\sqrt5}{\sqrt5}$ $=\frac{2\sqrt5}{5}$ $=\frac{2(2.236)}{5}$ $=\frac{4.472}{5}$ $=0.8945$ 2. $\frac{2-\sqrt3}{\sqrt3}$ $=\frac{2-\sqrt3}{\sqrt3}\frac{\sqrt3}{\sqrt3}$ $=\frac{2\sqrt3-3}{3}$ $=\frac{2(1.732)-3}{3}$ $=\frac{3.464-3}{3}$ $=\frac{0.464}{3}$ $=0.1546$ 3. $\frac{\sqrt{10}-\sqrt5}{\sqrt2}$ $=\frac{\sqrt{10}-\sqrt5}{\sqrt2}*\frac{\sqrt2}{\sqrt2}$ $=\frac{\sqrt{20}-\sqrt{10}}{2}$ $=\frac{2\sqrt{5}-\sqrt{10}}{2}$ $=\frac{2(2.236)-3.162}{2}$ $=\frac{4.472-3.162}{2}$ $=\frac{1.310}{2}$ $=0.655$