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is continuous at `x = 0`, thenA. `a = log_(e)b, a = 2/3`B. `b= log_(e)a, a = 2/3`C. `a = log_(e)b, b = 2`D. None of these |
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Answer» Correct Answer - A `f(0) = b` `f(0^(+)) = underset(hrarr0)(lim)e^((tan2h)/(tan3h))=e^(underset(hrarr0)(lim)(((tan2h)/(2h))2h)/(((tan3h)/(3h))3h))=e^(2//3)` `f(0^(-)) = underset(hrarr0)(lim)(1+|sin(-h)|).(a)/(|sin(-h)|) , :. 1^(oo)` `=e^(underset(hrarr0)(lim)[1+|sinh|-1].(a)/([sinh]))=e^(a)` `rArr {:(a=2//3),(b=e^(2//3)):}` |
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