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Is 4 is a factor of x^2+ y^2, where both x and y are odd positive Integers? |
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Answer» <P>Answer: Let the two odd positive numbers be X = 2k + 1 a nd y = 2p + 1 Hence x2 + y2 = (2k + 1)2 + (2p + 1)2 = 4k2 + 4k + 1 + 4p2 + 4P + 1 = 4k2 + 4p2 + 4k + 4p + 2 = 4(K2 + p2 + K + p) + 2 Clearly notice that the sum of square is even the number is not divisible by 4Hence if x and y are odd positive integers, then x2 + y2 is even but not divisible by 4 HOPE THIS ANSWER IS HELPFUL TO YOU |
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